Math, asked by badrinathmalepati, 10 months ago

Two pipes are used to fill the astern completely. The second pipe opened one hour after the
first pipe. Three hours after the first plpe has opened, there is still (9/20) of the cistern is to
be filled. When the cistern is completely filled, it was found that each pipe has filled half of
the astern. How many hours would it take each one to completely filled the cistem
individually?​

Answers

Answered by amitnrw
0

Given :   second pipe opened one hour after the first pipe. Three hours after the first plpe has opened, there is still (9/20) of the cistern is to

be filled.  When the cistern is completely filled, it was found that each pipe has filled half of the cistern

To find : How many hours would it take each one to completely filled the cistern individually

Solution:

Let say  Pipe A fill Cistern  in  A hrs

pipe A fills  in 1 hr  = 1/A

Let say  Pipe B fill Cistern  in  B hrs

pipe B fills  in 1 hr  = 1/B

3/A  +  2/B   =  1 -  9/20

=> 3/A  +  2/B   = 11/20

Let say Cistern filled in   n+ 1 hrs

Then     (n + 1)/A  =  n/B  = 1/2

=> A = 2(n + 1)

   B = 2n

3/A  +  2/B   = 11/20

=> 3/2(n +1)   + 2/2n    = 11/20

=> 3/(n + 1)  + 2/n  = 11/10

=>  30n  + 20n + 20   =  11n² + 11n

=> 11n² - 39n   - 20  = 0

=> 11n² - 44n + 5n - 20 = 0

=> 11n(n - 4) + 5(n - 4) = 0

=> (11n + 5) (n - 4) = 0

=> n = 4

A = 2(n + 1) = 10

B = 2n   = 8

Pipe A will fill in 10 hrs    & pipe B will fill in 8 hrs

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