Math, asked by nandarawat441983, 5 months ago

Two pipes can fill a cistern in 10 hours and 8 hours respectively. A third pipe can empty it in 15 hours. How long willit take to fill the cistern, if all of them are opened together ?
plz answer this correctly and i will thnk ur 4 answers​

Answers

Answered by KARTIKKING99
1

First tap can fill a cistern in 10 hours

Second tap can fill the cistern in 8 hours

Third tap can empty the cistern in 15 hours

∴ First tap’s 1 hour’s work = 1/10

Second tap’s 1 hour’s work = 1/8

And third tap’s 1 hour’s work = 1/15

If all of them are opened together, then

Their one hour’s work = 1/10 + 1/8 – 1/15

= (12 + 15 – 8)/120

= (27 – 8)/120

= 19/120

∴ They can fill the cistern in 120/90 hours

= 6.6/19 hours

Answered by Tanishk82
1

Answer:

6.3 hours

Step-by-step explanation:

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