Question

Two pipes can fill a cistern in 14 and 16 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom of the cistern, it takes 32 minutes extra for the cistern to be filled up. When the cistern is full, in what time will the leak empty it? *

Answer 1

Answer:

Step-by-step explanation:

Work done by the two pipes in 1 hr=[1/14+1/16]=15/112

Time taken by these pipes to fill the tank=112/15 hrs=(7hrs 28min)

Due to leakage,time taken=(7hrs 28min)+32 min=8hrs

work done by two pipes with leakage in 1 hr=1/8

work done by the leak in 1hr=[15/112-1/8]=1/112

leak will empty the cistern in 112 hrs

Hope it helps you....