Math, asked by badalsinghsrinet, 4 months ago

two pipes can fill a tank in 20 hours.f the ratio of capacities of the pipes are 2:3 . how much time each pipe will take to fill the tank alone​

Answers

Answered by ranadip83l
1

two pipes can fill a tank in 20 hours.f the ratio of capacities of the pipes are 2:3 . how much time each pipe will take to fill the tank aloneAnswer:

Time taken by pipe X to fill the tank = 20 hours

Time taken by pipe Y to fill the tank = 35 hours

Total capacity of tank = LCM of (20 and 35) = 140 units

Efficiency of pipe X = 140/20 = 7 units/hour

Efficiency of pipe Y = 140/35 = 4 units/hour

Efficiency of pipe X and Y together = 7 + 4 = 11 units/2 hours

Time taken to fill 132 units of tank = 132 × 2/11 = 24 hours

Remaining capacity = 140 - 132 = 8 units

Now its Y turn to fill.

Now Y fill 4 units in next 1 hour

Time taken to fill 136 units of tank = 24 + 1 = 25 hours

Now X fill the remaining 4 units.

Time taken by X to fill remaining 4 units = 4/7 hours

∴ Total time taken to fill the tank = 25 + 4/7 = 179/7 hours

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