Question

Two pipes can separately fill a tank in 3 hours and 2 houds respectively, if both the pipes are in operation in how much time will the tank be filled?​

Answer 1

Answer:

Step-by-step explanation:

Pipe A fills the tank in 2 hrs

Pipe A in 1 hr fills : 1/2 part of tank

Pipe B fills the tank in 3 hrs

Pipe B in 1 hr fills: 1/3 part of tank

In 1 hr, both fill:

1/2 + 1/3 = 3+2/6 = 5/6 part

1 hr=== 5/6 part

X hrs == 1 part

5X/6 = 1

X = 6/5 hours OR 6*60/5 = 72 mins or 1 hr 12 mins

So both the pipes working together will fill the tank in 72 mins or 1 hr 12 mins

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