Math, asked by sdsonaas, 5 hours ago

two pipes fil in 30 minutes and 40 minutes respectively third pipe empty the tank in 24 min . if all the pipes kept open the tank can be fill with in how many min​

Answers

Answered by aj200260
0

Answer:

60 mins

Step-by-step explanation:

Time taken by 1st pipe to fill the tank = 30 min

Time taken by 2nd pipe to fill the tank = 40 min

Time taken by 3rd pipe to empty the tank = 24 min

=1/30 + 1/40 - 1/24

=1/60

the tank can be filled in 60 mins if all the pipes are kept open

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Answered by sonakshi605
0

Answer:

time taken by A to fill the tank = 30 min

time taken by B to fill the tank = 40min

time taken by C to empty the tank = 24min

work done by pipe A in 1 mim = 1/30

". ". ". B ". ". = 1/40

". ". ". C. ". ". = 1 /24

work done by pipe abc together 1/30+1/40-1/24

=4+3-5/120

=2/120

1/60

so time taken by them together is 1/60

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