Question

two pipes running together can fill a cistern in 10/3 minutes. If one pipe takes 3 minutes more than the other to fill the cistern, find the time in which each pipe would fill the cistern

Answer 1

Answer:

5.49 and 8.49 minutes respectively.

Step-by-step explanation:

solving by unitary method.

first pipe fills in x minutes no of cisterns is 1 so in 1 min it fills = 1/x cistern.

second pipe fills in 3+x minutes no of cisterns is 1

so in 1 min it fills = 1/(3+x) cistern

together in 10/3 minutes they fill 1 cistern.

This can be written as:-

=>(10/3x)+(10/(3x+9))=1

=>(x+3+x)/(x^2+3x) = 3/10

=>20x+30 = 3x^2 + 9x

=>3x^2-11x-30= 0

on solving x is 5.49

and X+3 is 8.49

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