Math, asked by abbasist2577, 3 months ago

Two pipes running together can fill a cistern in 3 1/13 hrs If one pipe takes 2 minutes more than the other to fill the cistern find the time in which each pipe can seperately fill the cistern

Answers

Answered by paulkoeli9681
0

Let faster pipe takes x min to fill the cistern. To fill the cistern slower pipe take (x+3) min. In 3 1/13= 40/13 min the slower pipe filled the cistern= 40/13 × (1/x+3) = 40/13(x+3). Hence, Faster pipe takes 5 min to fill the cistern while slower pipe takes (x+3) = 5+3= 8 min to fill the cistern.

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