Math, asked by sabranahid, 2 months ago

two pipes running together can fill a cistern in 3 1/13 hrs . if one pipe take 3 hrs more than the other to fill it, find the time in which each pipe would fill the cister​

Answers

Answered by veeresh1937
0

Step-by-step explanation:

OUTLET: A pipe connected with a tank or a cistern or a reservoir, emptying it, is known as Outlet. A pipe can fill a tank in x hours, then: part filled in 1 hour = 1/x.

When a pipe can empty a tank in y hours, then: part emptied in 1 hour = 1/y.

If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours( where y>x), then on opening both the pipes, the net part filled in 1 hour=(1/x) – (1/y).

If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours (where x>y), then on opening both the pipes, the net part filled in 1 hour= [(1/y) – (1/x)].

Suppose two pipes can fill an empty

Similar questions