Question

two pipes running together can fill a cistern in 3 1/3 minutes.if 1 pipe takes 3 minutes more than the other to fill it,find the time in which each pipe would fill the cistern.

Answer 1

Let the first pipe would take x min to fill
And the second pipe take x+3 min to fill
Therefore 1/x + 1/x+3 = 1/40/13
3 1/3 min=40/13 min

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Answer 2

Answer:

First pipe takes 5 min to fill and the second pipe takes 8 min to fill the tank.

Solution:

Let us assume that the first pipe will take x min to fill the tank;

So the second pipe will take$(x+3)$ min to fill the tank.

Both the pipes take total $3 \frac{1}{3} m i n=\frac{40}{13} m i n$

So now, First pipe fill the part in 1 min is $\frac{1}{x}$

And second pipe fill the part in 1 min is $\frac{1}{x+3}$

So,

$\frac{1}{x}+\frac{1}{x+3}=\frac{13}{40}$

$\frac{2 x+3}{x^{2}+3 x}=\frac{13}{40}$

$80 x+120=13 x^{2}+39 x$

$(x-5)(13 x+24)=0$

$x=5 \text { or } x=-\left(\frac{24}{13}\right)$

As x value cannot be negative,

hence x =5,

First pipe take 5 min to fill and the second pipe take (5+3) = 8 min to fill the tank.