Question

Two pipes running together can fill a cistern in 30/11 minutes. Two pipes running together can fill a cistern in 30/11 minutes. If one pipe takes 1 minute more than the other to fill the cistern , find the time in which each pipe would fill the cistern
Pls ans fast

Answer 1

Let Volume per minute flowing through pipes be A and B.

Accordingly (A+B) (30/11) is volume of cistern

Let A take more time than B

⇒ A*(t+1) = B*t

⇒ B = A *(t+1)/t

So  A*(t+1) =  (A+B) (30/11)

⇒ A*(t+1) =  (A+A *(t+1)/t) (30/11)

⇒ t+1 = (2*t+1)/t * (30/11)

⇒ 11*(t^2+t ) = 60*t +30

⇒ 11*t² -49*t -30 = 0

⇒ t = 5 or -6/11

Since time is positive A takes 6 minutes and B takes 5 minutes individually