Question

Two pipes running together can fill a cistern in
30/11 min. If one pipe takes 1 min more than the

other to fill the cistern, then find the time in which
each pipe would fill the cistern.​

Answer 1

Answer:

Since time cannot be negative, x = 5 minutes. Hence time taken by the pipe that fills faster is 5 minutes and time taken by the pipe that fills slower is 8 minutes.

Step-by-step explanation:

Let the two pipe be A and B

Let time taken by A and B to fill the cistern individually be 'x' and 'x+1' minutes respectively.

Pipe A 1 minute work =

x

1

Pipe B 1 minute work =

x+1

1

Pipe A and B combined 1 minute work =

x

1

+

x+1

1

They take

11

30

minutes to fill the cistern together, there in 1 minute they will fill (

30

11

)

th

part of tank.

x

1

+

x+1

1

=

30

11

x(x+1)

x+1+x

=

30

11

x

2

+x

2x+1

=

30

11

30(2x+1)=11(x

2

+x)

60x+30=11x

2

+11x

11x

2

−49x−30=0

(11x+6)(x−5)=0

Since x cannot be negative

∴x=5

Hence pipe A will take 5 minutes and B will take 6 minutes.