Question

Two pipes running together can fill a cistern in 40/13 minutes.If one pipe takes 3 minutes more than the other to fill it,find the time in which each pipe would fill the cistern.

Answer 1

Let the time taken by first pipe to fill the cistern be x minutes
Therefore the time taken by the second pipe = (x – 3) minutes
Portion of cistern filled by first pipe=1/x 
Portion of cistern filled by second pipe=1/(x – 3) 
Given portion filled by two pipes simultaneously = 40/13 minutes
Hence, [1/x] + [1/( x – 3)] = 40/13  
13(2x – 3) = 40x(x – 3)
40x2 – 146x – 39 = 0
On simplification, we get
x = 3.9 or x = -0.25
Hence x = 3.9 since x cannot be negative
Therefore time taken by first pipe = 3.9 minutes and time taken by second pipe = 0.9 minutes

Answer 2

Step-by-step explanation:

I hope it will be helpful to you.