Question

two pipes running together can fill a cistern in 40/13 hours .if one pipe takes 3 minutes more than the other to fill the cistern .find the time in which each pipe can separately fill the cistern

Answer 1

the answer is as shown in the photo

Answer 2

Answer:

0.9 minutes

Step-by-step explanation:

Let the time taken by first pipe to fill the cistern be x minutes

Therefore the time taken by the second pipe = (x – 3) minutes

Portion of cistern filled by first pipe=1/x

Portion of cistern filled by second pipe=1/(x – 3)

Given portion filled by two pipes simultaneously = 40/13 minutes

Hence, [1/x] + [1/( x – 3)] = 40/13  

13(2x – 3) = 40x(x – 3)

40x2 – 146x – 39 = 0

On simplification, we get

x = 3.9 or x = -0.25

Hence x = 3.9 since x cannot be negative

Therefore time taken by first pipe = 3.9 minutes and time taken by second pipe = 0.9 minutes