Question

Two pipes running together can fill a cistern in 6 minutes. If one pipe takes 5 minutes more than the other to fill the cistern. find the time in which each pipe would fill the cistern

Answer 1

2 pipes can fill the cistern in 6 min.
1 pipe can fill the cistern in 6*2 min=12 min.
since,1 pipe takes 5 min then the other pipe would take 12-5=7 min.

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Let the time taken by 1st pipe be x minutes

And the time taken by the 2nd pipe be x + 5 minutes.

According to the Question,

⇒ 1/x + 1/x + 5 = 1/6

⇒ x + 5 + x/x(x + 5) = 1/6

⇒ 2x + 5/x² + 5x = 1/6

⇒ x² + 5x = 12x + 30

⇒ x² - 7x - 30 = 0

⇒ x² - 10x + 3x - 30 = 0

⇒ x(x - 10) + 3(x - 10) = 0

⇒ (x - 10)(x + 3) = 0

⇒ x = 10, - 3 (As x can't be negative)

⇒ x = 10

Time taken by 1st pipe = x = 10

Time taken by 2nd tap = x + 5 = 10 + 5 = 15