Question

two pipes running together can fill a tank in 3 1/3hours if one pipe takes 3hours more than the second pipe to fill the tank find the time in which each pipe would fill the tank ​

Answer 1

Let the time taken by the faster pipe to fill the cistern is x minutes, then the time taken the slower pipe will be (x+3) minutes.
The portion of cistern filled by the faster pipe in 1 minute is
x
1
​
.
The portion of cistern filled by the faster pipe in
13
40
​
minutes is
13x
40
​
.
The portion of cistern filled by the slower pipe in
13
40
​
minutes is
13(x+3)
40
​
.
As the cistern is filled fully in
13
40
​
minutes, then,
⇒
13x
40
​
+
13(x+3)
40
​
=1
⇒
x
1
​
+
(x+3)
1
​
=
40
13
​

⇒40(2x+3)=13(x+3)
⇒13x
2
−41x−120=0
⇒13x
2
−65x+24x−120=0
⇒(x−5)(13x+24)=0
∴x=5,x=−
13
24
​

∵ x can not be a negative
Therefore, the faster pipe will fill the cistern in 5 minutes and the slower pipe will fill the cistern in 5+3=8 minutes.

Answer 2

Answer:

Pipe will fill in 8 minutes

Step-by-step explanation:

Mark as brainliest answer