Question

Two pipes running together can fill a tank in 6hrs. The tap of larger diameter takes 9hr less than the smaller one to fill the tank separately. Find the time in which each tap cqn separately fill the tank. This question is frm Quadratic equation. plzz solve fast i will mark brainlist

Answer 1

hey friend!!!!


here is your answer ☞


Sol :

Let the tap of the larger diameter fills the tank alone in (x – 9) hours.

In 1 hour, the tap of the smaller diameter can fill 1/x part of the tank.

In 1 hour, the tap of the larger diameter can fill 1/(x – 9) part of the tank.

Two water taps together can fii a tank in 6 hours.

But in 1 hour the taps fill 1/6 part of the tank.

1 / x + 1 / (x – 9) = 1/6

[(x-9)+x] = x(x-9)/6

6x-54+6x = x²-9x

x²-21x+54=0

x²-18x-3x+54=0

x(x-18)-3(x-18) = 0

(x-3)(x-18)=0

then

{ X = 3, or. X = 18 }




But x = 3then 3 – 9 = -6 which is not possible since time

But x = 18 then 18 – 9 = 9

Larger diameter of the tap can the tank 9 hours and smaller diameter of the tank can fill
the tank in 18 hours.

hope it will help you..