Question

Two pipes running together then fill a cistern in 30/11 minutes. if one pipes takes 1 minutes more then the other to fill the cisterns, find the time in each pipe would fill the cistern

Answer 1

Let the speed to the cistern by first pipe be X and of second pipe be (x+1),
1/x+1/x+1=11/30
2x+1/x^2+x=11/30
60x+30=11x^2+11x
11x^2-49x-30=0
11x^2-55x+6x-30=0
11x(x-5)+6(x-5)=0
(11x+6)+(x-5)=0
x=5 or -6/11
x=5. (by leaving negative value)
so speed of pipe 1=5mins. and of pipe 2 is 6mins

Answer 2

Answer:

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