Two pipes together can fill a tank in 6 2/3 hours .if the pipe of smaller diameter takes 3hiurs more than the pipe of larger diameter to fill the tank seperately, find the time taken by each pipe to fill the tank separately?
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let the time taken by larger tank be x
time taken by smaller pipe is (3+x)
part of tank filled by larger pipe 1 hour = 1/x
part of tank filled by smaller pipe in 1 hour=1/3+x
time taken by both the tap is 20 /3
according to the questions
1/x+1/x+3 = 20/3
2x+3/x2 +3x =30/3
(2x+3 )3 =20× x2+3x
6x+9 = 20x2 + 60x
20x254x-9 =0
time taken by smaller pipe is (3+x)
part of tank filled by larger pipe 1 hour = 1/x
part of tank filled by smaller pipe in 1 hour=1/3+x
time taken by both the tap is 20 /3
according to the questions
1/x+1/x+3 = 20/3
2x+3/x2 +3x =30/3
(2x+3 )3 =20× x2+3x
6x+9 = 20x2 + 60x
20x254x-9 =0
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