Question

Two pistons of a hydraulic lift have area of 60 sq m and 5 sq m. What is the force exerted by the larger piston when 10 N is placed on the smaller piston?

Answer 1

Answer:

Small piston area: (3.14 x 5 x 5)/4 = 19.625 cm2

Larger pistom area: (3.14 x 60 x 60)/4 = 2826 cm2

In the small piston: P = F/A then P = 50N / 19.625 cm2 = 2.547 N/cm2

In the larger piston: P = F/A then 2.547 = F/2826 or F = 2826 x 2.547 = 7,200 N

Other way: square diameter ratio: square60 / square 5 or 3600/25 = 144 or the multiplication factor is 144 or 50 N x 144 = 7200 N