two pistons of a hydrolic lift have diameter if 50cm and 5cm what is the force exerted by the large piston when 60n is placed onthe smaller piston
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GIVEN:
F1 = 60N
F2 = ?
A1 = 05cm
A2 = 50cm
FORMULA USED:
F1/A1 = F2/A2
APPLYING FORMULA:
60N/5 = F2/50
=> F2 = (60×50) / 5
=> F2 = 600N
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