Question

two pistons of a hydrolic lift have diameter if 50cm and 5cm what is the force exerted by the large piston when 60n is placed onthe smaller piston​

Answer 1

GIVEN:

F1 = 60N

F2 = ?

A1 = 05cm

A2 = 50cm

FORMULA USED:

F1/A1 = F2/A2

APPLYING FORMULA:

60N/5 = F2/50

=> F2 = (60×50) / 5

=> F2 = 600N