Two pistons of hydraulic press have diameters of 30cm and 2.5cm what is the force exerted by a large piston when 50kg weight is placed on the smaller piston
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Now simplify and derive the final answer
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Area of piston = 22/7 × d²/4
F1÷22/7 × d1²/4 = F2 ÷ 22/7 ×d2²/4
F1/d1² = F2/d2²
50÷2.5×2.5 = F2÷30×30
F2 = 7200 kg wt
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