Question

Two pizzas of equal size are divided into 4 and 6 parts respectively. Deepti ate 2 slices of first pizza and
Ritu ate 2 slices of second pizza. Who ate more and by what fraction?​

Answer 1

Answer:

but not questions is complete okay

Answer 2

The given question is two pizzas of equal size divided into 4 and 6 parts respectively. Deepti ate 2 slices of the first pizza and Ritu ate 2 slices of the second pizza.

we have to find who ate more pizza and by what fraction.

Given, that two pizzas of equal size are divided into 4 and 6 parts respectively.

Let the total quantity of each pizza be 1.

Now, the quantity of each slice of the first pizza

$\begin{gathered} = 1 \times \frac{1}{4} \\ = \frac{1}{4} \end{gathered}$

and quantity of each slice of the second pizza

$\begin{gathered} = 1 \times \frac{1}{6} \\ = \frac{1}{6} \end{gathered}$

It is also given Deepti ate 2 slices of the first pizza.

So, Deepti ate a total of

$\frac{1}{4} \times 2 = \frac{1}{2} \: part \:$

It is also given that Ritu is 2 slices of the second pizza.

so, Ritu ate a total of

$\frac{1}{6} \times 2 = \frac{1}{3}$

As we know that

$\frac{1}{2} > \frac{1}{3}$

so, Deepti ate more pizza.

Deepti are more pizza than Ritu by the fraction

$\frac{1}{2} - \frac{1}{3} \\ \frac{3 - 2}{6} = \frac{1}{6}$

Therefore, the final answer to the question is

$\frac{1}{6}$

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