Question

Two pizzas of equal size are divided into 4 and 6 parts respectively. Rohit ate 2 slices of
the first pizza and Karan 2 slices of the second pizza. Who ate more and by what fraction​

Answer 1

Answer:

Rohit ate more pizza 2/4

Step-by-step explanation:

as the 1st pizza has only 4 pieces and rohit ate half of it so he has eaten more pizza.

Answer 2

Answer:

Rohit ate more and by $\frac{1}{6} \: fraction$

Step-by-step explanation:

Given,two pizzas of equal size are divided into 4 and 6 parts respectively.

Let total quantity of each pizza be 1.

Now, quantity of each slice of first pizza

$= 1 \times \frac{1}{4} \\ = \frac{1}{4}$

and quantity of each slice of second pizza

$= 1 \times \frac{1}{6} \\ = \frac{1}{6}$

It is also given Rohit ate 2 slice of first pizza.

So,Rohit ate total

$\frac{1}{4} \times 2 = \frac{1}{2} \: part \: of \: pizza$

Again Karan ate 2 slice of second pizza.

So,Karan ate total $\frac{1}{6} \times 2 \\ = \frac{1}{3} \: part \: of \: pizza$

It is clear that $\frac{1}{2} > \frac{1}{3}$

So we can say Rohit ate more pizza and by

$(\frac{1}{2} - \frac{1}{3} ) = \frac{3 - 2}{6} = \frac{1}{6} \: fraction$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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