Two places A and B are 120 km apart from each other on highway. One car starts from A and 5
another from B at the same time. If they move in same direction, they meet in 6 hours and if
they move in opposite directions, they meet in 1 hour and 12 minutes. Find the speeds of the
cars.
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- Let the speed of car I=xkm/hr
- And the speed of car II=ykm/hr
- Car I starts from point A and Car II starts from point B.
- Let two cars meet at C after 6h.
- Distance travelled by car I in 6h=6xkm
- Distance travelled by car II in 6h=6ykm
- since, they are travelling in same direction, sign should be negative 6x−6y=120
- ⇒x−y=20…(i)
- Now, Let two cars meet after 1 hr 12 min 1hr 12min=1+6012=56hr
- since they are travelling in opposite directions, sign should be positive.
- 56x+56y=120
- ⇒6x+6y=120×5
- ⇒x+y=100…(ii)
- On adding (i) and (ii) , we get x−y+x+y=20+100
- ⇒2x=120
- ⇒x=60
- Putting the value of x=60 in Eq. (i), we get 60−y=20
- ⇒y=40
- So, the speed of the two cars are 60km/hand 40km/hr respectively.
- hope it will help you!!
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