Math, asked by Ayush200595, 3 months ago

Two places A and B are 120 km apart from each other on highway. One car starts from A and 5
another from B at the same time. If they move in same direction, they meet in 6 hours and if
they move in opposite directions, they meet in 1 hour and 12 minutes. Find the speeds of the
cars.

Answers

Answered by Anonymous
38

\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}!

  • Let the speed of car I=xkm/hr 

  • And the speed of car II=ykm/hr

  • Car I starts from point A and Car II starts from point B. 

  • Let two cars meet at C after 6h. 

  • Distance travelled by car I in 6h=6xkm 

  • Distance travelled by car II in 6h=6ykm 

  • since, they are travelling in same direction, sign should be negative 6x−6y=120

  • ⇒x−y=20…(i)
  • Now, Let two cars meet after 1 hr 12 min 1hr 12min=1+6012=56hr

  • since they are travelling in opposite directions, sign should be positive.

  • 56x+56y=120

  • ⇒6x+6y=120×5

  • ⇒x+y=100…(ii)

  • On adding (i) and (ii) , we get x−y+x+y=20+100

  • ⇒2x=120

  • ⇒x=60
  • Putting the value of x=60 in Eq. (i), we get 60−y=20

  • ⇒y=40

  • So, the speed of the two cars are 60km/hand 40km/hr respectively.

  • hope it will help you!!
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