Question

Two places p and q are 400 miles apart.A car starts from p at a speed of 50 kmph towards q.After 75 min ,another car starts from q to p at a speed of 40 kmph.At what time will the cars meet

Answer 1

Answer:

7 hours 42 mins. 30 seconds from the time of starting the journey of Car A

Step-by-step explanation:

Let Car A starts from point p towards point q with a speed of 50 kmph.

Given Car A moves for 75 mins after which another Car B starts to move from point q towards point p with a speed of 40 kmph.

Also given that the distance between p and q points is 400 miles i.e. 643.738 km.

Now, after 75 minutes the Car A will be at $\frac{50*75}{60}=62.5$ km from point p.

The remaining distance of (643.738-62.5) = 581.238 km is covered by Car A and Car B together with a speed (50+40) = 90 kmph.

So, the time required to cover remaining 581.23 km. distance will be $\frac{60}{90}(581.238) = 387.5 minutes$ (Approximate) = 6 hrs.27 mins. 30 seconds.

Therefore, after ( 6 hrs. 27 mins. 30 seconds+75 mins.)=7 hours 42 mins. 30 seconds from the time of starting the journey of Car A, both the cars will meet with each other.

Answer 2

Step-by-step explanation:

I hope u got the answer..............