Question

Two plane mirrors m1 and m2 are inclined at 100 degree to each other . A ray of light is incident first on m1 at a glancing angle of 30 degree and later on m2 . find the angle of incidence

Answer 1

Answer:

Answer:=90°−θ

Answer:=90°−θβ=θ

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ∴δ=90°−(180°−2θ)=2θ−90°

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ∴δ=90°−(180°−2θ)=2θ−90°θ=90°−δ=90°−(2θ−90°)

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ∴δ=90°−(180°−2θ)=2θ−90°θ=90°−δ=90°−(2θ−90°)⟹θ=180°−2θ

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ∴δ=90°−(180°−2θ)=2θ−90°θ=90°−δ=90°−(2θ−90°)⟹θ=180°−2θ⟹3θ=180°

Answer:=90°−θβ=θ⟹θ+β+γ=180° (In △)⟹θ+θ+γ=180°∴γ=180°−2θ∵δ=90°−γ∴δ=90°−(180°−2θ)=2θ−90°θ=90°−δ=90°−(2θ−90°)⟹θ=180°−2θ⟹3θ=180°∴θ=60°