Question

two planes x-2y+4z=10 and 18x+17y+kz=50 ate perpendicular, if k is​

Answer 1

Answer:

18+-34+4k=0 -16+4k=0 k=4

Answer 2

The value of k for which the two planes x-2y+4z=10 and 18x+17y+kz=50 are perpendicular is equal to 4.

For the two planes two be perpendicular , their dot product should be equal to zero.

The dot product of x-2y+4z=10 and 18x+17y+kz=50 should be zero for the two planes to be perpendicular.

(-1,2,4).(18,17,k) = 0

=> -18 + 34 +4k = 0

=> k = 4

The value of k is equal to 4.