Question

Two plate each of charge 1microcoulomb are located 3cm apart in air then find electric force between them

Answer 1

Answer:

10N

Explanation:

Electrostatic force of attraction :

Q1 = Q2 = Q = 1 micro-coulomb or  coulomb

Distance between ( r )  = 3 cm or ( 3 x  ) m

Using coulomb law of Electrostatic force :

F = [ ( 9 x  ) x ( Q1 . Q1) ] /

Solving the above expression we get :

F = 10 N