Math, asked by pamjdv1149, 1 year ago

Two players share an unbiased coin and take it in turns to play "the race". On player 1's turn, he tosses the coin once: if it comes up heads, he scores one point; if it comes up tails, he scores nothing. On player 2's turn, she chooses a positive integer and tosses the coin times: if it comes up all heads, she scores points; otherwise, she scores nothing. Player 1 goes first. The winner is the first to or more points.

Answers

Answered by amitnrw
1

Answer:

for t = 2 she has maximum probability  to win

Step-by-step explanation:

Player 1  getting head probability = 1/2

to Score 100 points he probably needs 200 turns

Player 2 select number t

Probability that all head turned up = (1/2)^t

Points she get = 2t-1

let say t = 1

probability of turning head = 1/2

Point she get = 2*1 - 1 = 1

to score 100 point probably she need 200 turns

she turns second so she has lesser chance to win

let say t = 2

probability of turning head = (1/2)² = 1/4

Probability she won in a turn  is 1 out of 4

Point she get = 2*2 - 1 = 3

to score 100 or more point probably she need to win min 34 turns so turns required to win 34 time = 34 * 4 = 136 turns only

She has more chances to win

let say t = 3

probability of turning head = (1/2)³= 1/8

Point she get = 2*3 - 1 = 5

to score 100 or more point probably she need 160 turns

She has more chances to win but more turns required compared to t=2

let say t = 4

probability of turning head = (1/2)⁴= 1/16

Point she get = 2*4 - 1 = 7

to score 100 or more point probably she need 240 turns

She has less chances to win

for t = 2 she has maximum probability

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