two plots of land have same perimeter one is a square of side 64m and the other is a rectangle of length 70m find the breadth of rectangular plot which plot has the greater area and by how much
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Perimeter of the square =4×64=256m
Area of the square =64^2=4096m^2
Given
Perimeter of the square =Perimeter of rectangle
So, Perimeter of the rectangle =256m
2 (l+b)=256
70+b=128
b=58m
Area of rectangle = lb=58×70=4060m^2
So,Area of the square is greater than area of rectangle by 36m^2
Area of the square =64^2=4096m^2
Given
Perimeter of the square =Perimeter of rectangle
So, Perimeter of the rectangle =256m
2 (l+b)=256
70+b=128
b=58m
Area of rectangle = lb=58×70=4060m^2
So,Area of the square is greater than area of rectangle by 36m^2
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Answer:
36 square metre
Step-by-step explanation:
Perimeter of the square =4×64=256m
Area of the square =64^2=4096m^2
Given
Perimeter of the square =Perimeter of rectangle
So, Perimeter of the rectangle =256m
2 (l+b)=256
70+b=128
b=58m
Area of rectangle = lb=58×70=4060m^2
So, Area of the square is greater than area of rectangle by 36m^2
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