Two plots of land have same perimeter. One is so
of side 60m & other other is a rectangle of break
& by how much?
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Answered by
0
Step-by-step explanation:
Length of the square =64 m
Length of the rectangle =70 m
Perimeter of the square =4×side=4×64=256 m
Let breadth of the rectangle =B
Perimeter of the rectangle =2(70+B)
Now, according to question,
2×(70+B)=256
⇒140+2B=256
⇒2B=256−140
⇒2B=116
⇒B=58 m
Area of the rectangle =58×70=4060 sq. m
Area of the square = length × breadth =64×64=4096 sq.m
Square has more area by 36 sq. m.
Answered by
0
Step-by-step explanation:
2b=116
b=58m
area of rectangle =58*70=4060m²
area of square =s*s
=64*64=4090m²
therefore, square has more area by 36m²
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