Question

two plots of land have the same perimeter. one is a square of side 50m​

Answer 1

Step-by-step explanation:

Length of the square =64 m

Length of the rectangle =70 m

Perimeter of the square =4×side=4×64=256 m

Let breadth of the rectangle =B

Perimeter of the rectangle =2(70+B)

Now, according to question,

2×(70+B)=256

⇒140+2B=256

⇒2B=256−140

⇒2B=116

⇒B=58 m

Area of the rectangle =58×70=4060 sq. m

Area of the square = length × breadth =64×64=4096 sq.m

Square has more area by 36 sq. m.

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Answer 2

Step-by-step explanation:

Length of the square =64 m

Length of rectangle =70m

perimeter of the square

4×side =4 × 64=256m

Let Length of the rectangle =B

Perimeter of the rectangle =2 (70+B)

Now according to question ,

2×(70+B )=256

=> 140 +2B =256

=> 2B =256-140

=> 2B =116

=> B =58m

Area of the rectangle =58×70=4060sq.m

Area of square =length ×breadth

=> 64×64=4096sq.m

Square has more area by 36 Sq. m

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