Two plots of land have the same perimeter. One is a square of side 64m and the other a rectangle with length 80m. Which plot has the greater area and by how much
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Answered by
41
perimeter of square=4s
s=64 m
perimeter of square=4×64=256
perimeter of square =perimeter of rectangle
perimeter of rectangle =256 m
perimeter of rectangle =2(l+b)
256=2(80+b)
256=160 +2b
96/2=b
b=48 m
Area of square= s^2=4096
Area of rectangle =l×b=80×48=3840
Square has more area
s=64 m
perimeter of square=4×64=256
perimeter of square =perimeter of rectangle
perimeter of rectangle =256 m
perimeter of rectangle =2(l+b)
256=2(80+b)
256=160 +2b
96/2=b
b=48 m
Area of square= s^2=4096
Area of rectangle =l×b=80×48=3840
Square has more area
Krishnagupta11:
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Answered by
9
perimeter of the square=4a
=4.64m= 256m
since the perimeter are equal to each other,
therefore,
perimeter of the rectangle =2(l+b)
256=2(80+b)
256/2=80+b
128=80+b
128-80=b
48=b
now,
area of the square=a square
=64m.64m=4096m square
again,
area of the rectangle=l.b
=80m.48m=3840m square
therefore from the above we got that area of the square has greater area by 4096m square
=4.64m= 256m
since the perimeter are equal to each other,
therefore,
perimeter of the rectangle =2(l+b)
256=2(80+b)
256/2=80+b
128=80+b
128-80=b
48=b
now,
area of the square=a square
=64m.64m=4096m square
again,
area of the rectangle=l.b
=80m.48m=3840m square
therefore from the above we got that area of the square has greater area by 4096m square
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