two plots of land have the same perimeter. one is a square of side 64 my and the other is a rectangle of length 70 m. find the breadth of the rectangular plot . which plot has the greater area and by how much?
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To find the second side of the rectangle, find the perimeter of the square(as they have the same perimeter) and substract 2*70 from it, then divide by 2.
=> Perimeter of square => 64*4 = 256m.square
=> Breadth of rectangle => 256-(2*70) /2 => 256-140 /2 => 116/2 = 58m
Therefore area of:-
Sqaure=> 64*64 = 4096m.square
Rectangle=> 70*58 = 4060m.square
Therefore the Square has a greater area.
Hope this helps!!!
jitendrakumarsingh36:
but the answer is not coming on my mobile's screen.
sorry for this but you please give me the another answer of this question.
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To find the second side of the rectangle, find the perimeter of the square(as they have the same perimeter) and substract 2*70 from it, then divide by 2.=> Perimeter of square => 64*4 = 256m.square=> Breadth of rectangle => 256-(2*70) /2 => 256-140 /2 => 116/2 = 58mTherefore area of:-Sqaure=> 64*64 = 4096m.squareRectangle=> 70*58 = 4060m.squareTherefore the Square has a greater area.Hope this helps!!!
thank you for this answer. say with me be the best.
To find the second side of the rectangle, find the perimeter of the square(as they have the same perimeter) and substract 2*70 from it, then divide by 2. => Perimeter of square => 64*4 = 256m.square =>Breadth of rectangle => 256-(2*70) /2 => 256-140 /2 => 116/2 = 58m Therefore area of:- Sqaure=> 64*64 = 4096m.square Rectangle=> 70*58 = 4060m.square Therefore the Square has a greater area. Hope this helps!!!
Sry sent it twice
Be the best:)
hahaha.thanks for this.
Your welcome!
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