two plots of land have the same perimeter . One square of side 64 m and the other is rectangle length 70m .find the breadth of the rectangular plot . which plot has the greater area and by how much
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perimeter of square=4a
4×64= 256m
perimeter of square=perimeter of rectangle( given)
4a=2(l+b)
4×64=2(70+b)
256=140+2b
2b=256-140
2b=116
b=116÷2
b=58m Ans
4×64= 256m
perimeter of square=perimeter of rectangle( given)
4a=2(l+b)
4×64=2(70+b)
256=140+2b
2b=256-140
2b=116
b=116÷2
b=58m Ans
Answered by
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Answer:
b = 58 m
area of square is greater than the area of rectangle by 36 m²
Step-by-step explanation:
2(l+b) = 4a
2(70+b) = 4*64
70+b = 4 *64/2 =128
b = 128-70
b = 58 m
Area of rectangle = lb = 70*58 = 4060 m²
Area of square = a*a = 64*64 = 4096 m²
∴ area of square is greater than the area of rectangle by 36 m²
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