two plots of land have the same primeter. one is a square of side 40m. while the other is a rectangle of bradth 25. which plots is larger and by how much.
lakshay10082008:
DIRECT ANSWER:-1425m
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Answered by
58
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▶ Question :-
→ Two plots of land have the same perimeter. One is a square of side 40m. While the other is a rectangle of breadth 25m . which plots is larger area and by how much.
▶ Answer :-
→ Square plot has larger area by 225 m² .
▶ Step - by - step explanation:-
➡ Given :-
→ Perimeter of square plot = Perimeter of rectangle plot .
→ Side of square plot = 40 m.
→ Breadth of rectangle plot = 25 m.
➡ To find :-
→ Which plot is larger and by how much .
We have ,
→ Perimeter of square plot = Perimeter of rectangle plot.
==> 4 × side = 2( l + b ) .
==> 4 × 40 = 2( l + 25 ) .
==> 160 = 2l + 50 .
==> 160 - 50 = 2l .
==> 2l = 110 .
==> l = 110/2 .
•°• l = 55 m.
→ Area of square = ( side ) ² .
= (40)² .
= 1600 m² .
→ Area of rectangle = l × b .
= 55 × 25 .
= 1375 m² .
✔✔ Hence, the square plot has larger area by [ 1600 - 1375 ] 225 m² ✅✅.
THANKS
#BeBrainly.
Answered by
30
Perimeter of square plot = Perimeter of rectangle plot.
4 × side = 2( l + b ) .
4 × 40 = 2( l + 25 ) .
160 = 2l + 50 .
160 - 50 = 2l .
2l = 110 .
l = 110/2 .
l = 55 m.
Area of square = ( side ) ² .
= (40)² .
= 1600 m² .
Area of rectangle = l × b .
= 55 × 25 .
= 1375 m² .
Therefore, the square plot has larger area by [ 1600 - 1375 ] 225 m² .
4 × side = 2( l + b ) .
4 × 40 = 2( l + 25 ) .
160 = 2l + 50 .
160 - 50 = 2l .
2l = 110 .
l = 110/2 .
l = 55 m.
Area of square = ( side ) ² .
= (40)² .
= 1600 m² .
Area of rectangle = l × b .
= 55 × 25 .
= 1375 m² .
Therefore, the square plot has larger area by [ 1600 - 1375 ] 225 m² .
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