two point chages q1=3µc and q2=1.5µc are placed 1m apart. calculate (i) electric feild strength at mid point of the line joining the charges (ii) electric potential at mid point of the line joining the charges
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Two charges placed at points A and B are represented in the given figure. O is the mid-point of the line joining the two charges.
Magnitude of charge located at A, q1 = 1.5 μC
Magnitude of charge located at B, q2 = 2.5 μC
Distance between the two charges, d = 30 cm = 0.3 m
(a) Let V1 and E1 are the electric potential and electric field respectively at O
V1 = Potential due to charge at A + Potential due to charge at B
Where, ∈0 = Permittivity of free space
E1 = Electric field due to q2 - Electric field due to q1
Therefore, the potential at mid-point is 2.4 × 105 V and the electric field at mid-point is 4 × 105 V m - 1. The field is directed from the larger charge to the smaller charge.
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