Question

Two point charge 0.2 and 0.4.find the electric field at a point 0.05m from 0.4 and .15 m from 0.2

Answer 1

The E=q÷r² in air in cgs

let,Q1=0.4esu ,and r1=0.05m=5cm

And Q2=0.2esu and r2=0.15m=15cm

(i) So, from Q1 charge Electric field at 5 cm

E1=0.4/5²

→E1=4/250

→E1=0.016,

here the electric field due to 0.2esu charge in negeable

So,

E1=0.016dyn/esu

Ans...

(ii) And, from 0.2esu charge electric field at 15 cm

E2=0.2/15²

→E2=0.2/225

→E2=2/2250

→E2=0.00089

Here the electric field due to 0.4 esu charge let be negeable

So,

E2=0.00089dyn/esu

Ans.....