Physics, asked by mimogoswami1325, 7 months ago

Two point charge =+2μC and =-2μC are placed at a distance of 10 cm in air/vacuum. ¼a½ Calculate the electric field intensity along the center of line joining the two chages. ¼b½ If a test charge = -1.2XC is placed at center of the PQ write the value of force acting on test charge and its direction.

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Answered by adityadwivedi1709
0

two-point charge qp=+2ohm c and qq=-2ohmc are placed at a distance of 10cm in air/vacuum.

a calculate the electric field intensity along the center of the line joining the two charges

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