Two point charge +3 mueC and +8 mueC repeal each other with a force of 40 N. If a charge of -5mueC is added to each of them . The force between them will be
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Answer:
10 N.
Explanation:
According to Coloumb's law
F= KQq/r^2
r^2 =KQq/F
given,
F= 40 N
Q=+8 μC
q=+3 μC
hence ,
r^2 = K (8)(3)/40= 3K/5 ----------(1)
again ,
when -5 μC added with each of them
Q'= +8-5= +3 μC
q"=+3 -5 =-2 μC
then ,
F' =KQ'.q'/r^2
=K (3)(2)/r^2
put equation (1)
F' =6K/(3K/5)=10N
Therefore,
Force=10N
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