Question

Two point charge of + 10 microcoulomb and - 10 microcoulomb are placed at a distance 40 cm in a potential energy of the system will be

Answer 1

Answer: -2.25J

Explanation:

P.E. = kq1q2/r    

Given:

q1= +10microCoulomb or  10^-6Coulomb,    

q2 = -10microCoulomb or 10^-6Coulomb ,

r= 40cm or 4x10^-1 m

As,

 P.E. = kq1q2/r

       = 9x10^9x10x-10x10^-12/4x10^-1

       = -9/4

      = -2.25 J    Ans.

Answer 2

Answer:-2.25J

Explanation:

The formula for potential energy depends on the force acting on the two objects, for the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters. ,

P.E. = kq1q2/r    

q1= +10microCoulomb or  10^-6Coulomb,    

q2 = -10microCoulomb or 10^-6Coulomb ,

r= 40cm or 4x10^-1 m

P.E. = kq1q2/r= 9x10^9x10x-10x10^-12/4x10^-1= -9/4

       = -2.25 J    

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