Question

two point charge of each charge q is placed at 2 opp. corner of square

Answer 1

Answer:

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Explanation:

A charge Q is placed at each of two opposite corners of a square

A charge Q is placed at each of the two opposite corners of a square. A charge q is placed at each of the other two comers. If the resultant force on each charge q is zero, then : A .

Answer 2

Given:

2 point charge of magnitude Q is placed at two opposite corners of a square. A third charge is placed at the centre of the square.

To find:

Net force experienced by the charge at the centre.

Calculation:

Let edge of square be d .

Hence diagonal of Square will be :

$\boxed{diagonal = \sqrt{ {d}^{2} + {d}^{2} } = d \sqrt{2} }$

Hence distance from the corner charge to the centre charge will be half of the diagonal.

$\boxed{distance = \dfrac{d \sqrt{2} }{2} = \dfrac{d}{ \sqrt{2} } }$

Net force on the middle charge will be :

$\sf{net \: f = \dfrac{kQq}{ {( \frac{d}{ \sqrt{2} }) }^{2} } - \dfrac{kQq}{ {( \frac{d}{ \sqrt{2} }) }^{2} } }$

$\sf{ = > net \: f = \dfrac{2kQq}{ {d}^{2} } - \dfrac{2kQq}{ {d }^{2} } }$

$\sf{ = > net \: f = 0}$

Hence , final answer will be :

Net force on middle charge is 0 N.