Question

Two point charge q and -q are placed at a distance 2a apart calculate the electric field at a point p situated at a distance r along the perpendicular bisector of the line joining the charge what is the field when r .. a​

Answer 1

Answer:

when point p is the perpendicular bisectors than it is lie on equatorial line.

hence E=

$9 \times {10}^{9} \: p \div {r}^{3}$

Explanation:

if the p lie on the axial line then Electric field E=

$9 \times {10}^{9} \: 2p \div {r}^{3}$