Question

two point charges 0.01micro coulomb and -0.01micro coulomb are placed 10 cm apart in vacuum. calculated the magnitude of electric field intensity at the middle point of the line joining the charges and mention its direction​

Answer 1

Answer:

Let a point p in middle now place two points at corner.

Explanation:

Here, one distance is x and other is 10- x..

Now, .01k/x square is it. Is equals to K. 2. 0 1 upon 10 - X ka whole square now

hundred plus x square - 20 X equal to x square and hence the Axe square cancelled by each other now the access = 200 upon 20 which is equals to 5 handset distance is equals to 5 centimetre.