Question

Two point charges 0.1mC and 0.05mC are kept at points(2m,0,0)and (-2,0,0).Calculate the electrostatic potential energy of the system

Answer 1

Explanation:

$u = kq1q2 \div r \\ u = 9 \times {10}^{ - 9} \times {10}^{ - 4} \times {10}^{ - 5} \times 5 \div 4 = 11.25 \times {10}^{ - 18 \\ }$