Two point charges 1×10^-8 and 4×10^-8 C are 0.06m apart in air . find the location of the point between them at which resultant electric field is zero
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Answers
Therefore 0.02 m from the charge 10^-8 C, electric field is zero.
Given : Two point charges 10^-8 C and 4 × 10^-8 C are 0.06 m apart in air.
To find : the position of the point between them at which resultant electric field is zero.
solution : as both charges are positive, electric field will be zero between them.
let x distance from the first charge, electric field will be zero.
electric field due to first charge + electric field due to 2nd charge = 0
⇒k(10^-8)/x² - k(4 × 10^-8)/(0.06 - x)² = 0
⇒1/x² = 4/(0.06 - x)²
⇒1/x = 2/(0.06 - x)
⇒0.06 - x = 2x
⇒0.06 = 3x
⇒x = 0.02 m
Therefore 0.02 m from the charge 10^-8 C, electric field is zero.
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