Question

two point charges +16q and -4q located at x=0 and x=L respectively. the location of a point on the x axis from x=0, at which the net electric field due to these 2 charges is zero is...

Answer 1

+16q _________________-4q______P____
                         L                                  x

Since, the positive charge is greater than the negative charge so The neutral point will be on the right of the negative charge as shown above

=>               16/(L+x)² = 4/(x)²
=>                 4 = {(L+x)/x}²
=>                 (2)² = ( L/x + 1) ²
=>                 L/x +1 = 2
=>                 x = L

So, The Neutral point is L units right to the Negative charge

Answer 2

Answer:

Explanation: unlike charge location formula

X=d√q2÷√q1+√q2 than given