Question

Two point charges 2 μC and 8 μC are placed at x = 0 m and x = 3 m on x-axis respectively. The position between the two charges where net electric field is zero is x = 1 m x = 2 m x = 1.5 m x = 1.25 m

Answer 1

The position between the two charges where net electric field is zero is x = 1

Therefore, option (1) is correct.

Explanation:

We know that electric field due to a charge q, at a distance is given by

$\boxed{E=k\frac{q}{r^2}}$  (where k is Coulomb's constant)

The given charges are 2 µC and 8 µC and distance between them is 3 m

Let electric field is zero at a distance x from 2 µC charge

Then

$k\frac{2}{x^2}=k\frac{8}{(3-x)^2}$

$\implies \frac{1}{x^2}=\frac{4}{(3-x)^2}$

$\implies (3-x)^2=4x^2$

$\implies x^2-6x+9=4x^2$

$\implies 3x^2+6x-9=0$

$\implies x^2+2x-3=0$

$\implies x^2+3x-x-3=0$

$\implies x(x+3)-1(x+3)=0$

$\implies (x-1)(x+3)=0$

$\implies x=-3,1$

But x cannot be negative

Therefore, x=1

Thus, the position on x -axis where net field is zero is x = 1

Hope this answer is helpful.

Know More:

Q: 2 point charges of +16 microcoulomb and -9 microcoulomb are placed 8 cm apart in air. Determine the position of the point where resultant electric field is 0 ( zero).justify with diagram.

Click Here: https://brainly.in/question/1717038

Q: Two charges 2 µC and -2 µC are placed at points A and B 6 cm apart. (a) Identify an equipotential surface of the system. (b) What is the direction of the electric field at every point on this surface?

Click Here: https://brainly.in/question/4601194