Question

two point charges 2 microcoulomb and 3 microcoulomb are separated by 3 mm in free space. the work done to bring them closer by 1 mm is​

Answer 1

Answer:

hope this is the correct answer

Answer 2

WORK DONE to move the charges closer to one another will be the difference in potential energy in the initial and final state:

$\rm \: W= PE2 - PE1$

$\rm \implies \: W= \dfrac{k(q1)(q2)}{d2} - \dfrac{k(q1)(q2)}{d1}$

$\rm \implies \: W= k(q1)(q2) \bigg( \dfrac{1}{d2} - \dfrac{1}{d1} \bigg)$

$\rm \implies \: W= (9 \times {10}^{9} \times 2 \times 3 \times {10}^{ - 12}) \bigg( \dfrac{1000}{2} - \dfrac{1000}{3} \bigg)$

$\rm \implies \: W= 54 \times \bigg( \dfrac{1}{2} - \dfrac{1}{3} \bigg)$

$\rm \implies \: W= 54 \times \bigg( \dfrac{3 - 2}{6} \bigg)$

$\rm \implies \: W= 54 \times \bigg( \dfrac{1}{6} \bigg)$

$\rm \implies \: W= 9 \: joule$

So, work done is 9 Joule.